2002 AMC 10B Problem 1

Attempt Problem 1 of the 2002 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 10B solutions, or check the answer key.

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1.

What is the value of the ratio

22001⋅3200362002?\dfrac{2^{2001} \cdot 3^{2003}}{6^{2002}}?

16\dfrac{1}{6}

13\dfrac{1}{3}

12\dfrac{1}{2}

23\dfrac{2}{3}

32\dfrac{3}{2}

Answer: E
Concepts:exponent
Difficulty rating: 770
Small Hint:

Write 620026^{2002} as 22002⋅320022^{2002}\cdot 3^{2002}

Big Hint:

Cancel the common powers of 22 and 33 from top and bottom

Solution:

Since 62002=22002⋅32002,6^{2002} = 2^{2002}\cdot 3^{2002}, the ratio becomes 22001⋅3200322002⋅32002=32.\dfrac{2^{2001}\cdot 3^{2003}}{2^{2002}\cdot 3^{2002}} = \dfrac{3}{2}.

Thus, the correct answer is E.

Full Exam

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