2009 AMC 10A 第 13 题

先试着解答 2009 AMC 10A 第 13 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2009 AMC 10A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

13.

设 P=2mP = 2^m、Q=3nQ = 3^n。下列哪一项对任意整数对 (m,n)(m, n) 都等于 12mn12^{mn}?
Suppose that P=2mP = 2^m and Q=3n.Q = 3^n. Which of the following is equal to 12mn12^{mn} for every pair of integers (m,n)?(m, n)?
P2QP^2 Q
PnQmP^n Q^m
PnQ2mP^n Q^{2m}
P2mQnP^{2m} Q^n
P2nQmP^{2n} Q^m
答案:E
知识点:指数质因数分解
小提示:
写出 12=22⋅312 = 2^2 \cdot 3,再取 mnmn 次方。
Write 12=22⋅312 = 2^2 \cdot 3 and raise it to the power mnmn
大提示:
用 P=2mP = 2^m 和 Q=3nQ = 3^n 重新组合 22mn⋅3mn2^{2mn} \cdot 3^{mn}。
Regroup 22mn⋅3mn2^{2mn} \cdot 3^{mn} using P=2mP = 2^m and Q=3nQ = 3^n
解答:
因为 12=22⋅312 = 2^2 \cdot 3,12mn=22mn⋅3mn=(2m)2n⋅(3n)m=P2nQm。 \begin{aligned} 12^{mn} &= 2^{2mn} \cdot 3^{mn} \\ &= (2^m)^{2n} \cdot (3^n)^m \\ &= P^{2n} Q^m \end{aligned}\text{。}
所以正确答案是 E。
Since 12=22⋅3,12 = 2^2 \cdot 3, 12mn=22mn⋅3mn=(2m)2n⋅(3n)m=P2nQm. \begin{aligned} 12^{mn} &= 2^{2mn} \cdot 3^{mn} \\ &= (2^m)^{2n} \cdot (3^n)^m \\ &= P^{2n} Q^m. \end{aligned}
Thus, the correct answer is E.
LIVE by Po-Shen Loh
LIVE项目

LIVE直播课程

Self-Paced录播课程

启明星Star计划

奖学金项目

关于我们

罗博深是谁?

邮件联系

订阅英文简报

加入我们

申请明星导师

For a more Thought Full world.

© 2026 Expii, Inc.