2007 AMC 10A Problem 13

Below is the professionally curated solution for Problem 13 of the 2007 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 10A solutions, or check the answer key.

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Concepts:distance rate and timeratio and proportion

Difficulty rating: 1420

13.

Yan is somewhere between his home and the stadium. To get to the stadium he can walk directly to the stadium, or else he can walk home and then ride his bicycle to the stadium. He rides 77 times as fast as he walks, and both choices require the same amount of time. What is the ratio of Yan's distance from his home to his distance from the stadium?

23\dfrac{2}{3}

34\dfrac{3}{4}

45\dfrac{4}{5}

56\dfrac{5}{6}

67\dfrac{6}{7}

Solution:

Let xx and yy be Yan's distances from home and from the stadium, and let ww be his walking speed.

Walking to the stadium takes yw.\dfrac{y}{w}. Walking home and biking takes xw+x+y7w.\dfrac{x}{w} + \dfrac{x + y}{7w}.

Setting these equal gives 7y=8x+y,7y = 8x + y, so 8x=6y8x = 6y and xy=34.\dfrac{x}{y} = \dfrac{3}{4}.

Thus, the correct answer is B.

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