2004 AMC 10B Problem 13

Below is the professionally curated solution for Problem 13 of the 2004 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 10B solutions, or check the answer key.

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Concepts:place valuedecimalbounding to limit cases

Difficulty rating: 1530

13.

In the United States, coins have the following thicknesses: penny, 1.551.55 mm; nickel, 1.951.95 mm; dime, 1.351.35 mm; quarter, 1.751.75 mm. If a stack of these coins is exactly 1414 mm high, how many coins are in the stack?

77

88

99

1010

1111

Solution:

Each thickness ends with 55 in the hundredths place. A stack of an odd number of coins keeps a 55 there, and pairs give an odd digit in the tenths place, so a whole-number height requires the count to be a multiple of 4.4.

A stack of 44 coins is at most 4(1.95)=7.84(1.95) = 7.8 mm, and a stack of 1212 coins is at least 12(1.35)=16.212(1.35) = 16.2 mm, so only 88 coins can total 1414 mm.

Indeed, 88 quarters give 8(1.75)=148(1.75) = 14 mm.

Thus, the correct answer is B.

Problem 13 in Other Years