2009 AMC 10A Problem 14
Below is the professionally curated solution for Problem 14 of the 2009 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 10A solutions, or check the answer key.
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Difficulty rating: 1340
14.
Four congruent rectangles are placed as shown. The area of the outer square is times that of the inner square. What is the ratio of the length of the longer side of each rectangle to the length of its shorter side?
Solution:
Let each rectangle have shorter side and longer side The outer square has side length and the inner square has side length
Since the area ratio is the side ratio is so which gives
The ratio of longer to shorter side is
Thus, the correct answer is A.
Problem 14 in Other Years
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