2009 AMC 10A Problem 14

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Concepts:area ratiorectanglelinear equation

Difficulty rating: 1340

14.

Four congruent rectangles are placed as shown. The area of the outer square is 44 times that of the inner square. What is the ratio of the length of the longer side of each rectangle to the length of its shorter side?

33

10\sqrt{10}

2+22 + \sqrt{2}

232\sqrt{3}

44

Solution:

Let each rectangle have shorter side xx and longer side y.y. The outer square has side length y+xy + x and the inner square has side length yx.y - x.

Since the area ratio is 4,4, the side ratio is 2,2, so y+x=2(yx),y + x = 2(y - x), which gives y=3x.y = 3x.

The ratio of longer to shorter side is yx=3.\dfrac{y}{x} = 3.

Thus, the correct answer is A.

Problem 14 in Other Years