2018 AMC 10B Problem 14

Below is the professionally curated solution for Problem 14 of the 2018 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10B solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:modeoptimization

Difficulty rating: 1660

14.

A list of 20182018 positive integers has a unique mode, which occurs exactly 1010 times. What is the least number of distinct values that can occur in the list?

202202

223223

224224

225225

234234

Solution:

The mode shows up 1010 times. To keep the number of distinct values small, let every other value repeat as much as the rules allow, which is 99 times each (any more would tie the mode). With dd distinct values the list holds at most 10+9(d1)10 + 9(d-1) entries. We need 10+9(d1)2018,10 + 9(d-1) \ge 2018, so d1223.1,d - 1 \ge 223.1, giving d225.d \ge 225. Therefore, the answer is D.

Problem 14 in Other Years