2008 AMC 10A Problem 14

Below is the professionally curated solution for Problem 14 of the 2008 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 10A solutions, or check the answer key.

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Concepts:ratio and proportionPythagorean Theoremrectangle

Difficulty rating: 1410

14.

Older television screens have an aspect ratio of 4:3.4:3. That is, the ratio of the width to the height is 4:3.4:3. The aspect ratio of many movies is not 4:3,4:3, so they are sometimes shown on a television screen by "letterboxing" — darkening strips of equal height at the top and bottom of the screen, as shown. Suppose a movie has an aspect ratio of 2:12:1 and is shown on an older television screen with a 2727-inch diagonal. What is the height, in inches, of each darkened strip?

22

2.252.25

2.52.5

2.72.7

33

Solution:

Since the screen is 4:34:3 with a 2727-inch diagonal, h:w:27=3:4:5,h : w : 27 = 3 : 4 : 5, giving height h=3527=16.2h = \dfrac{3}{5}\cdot 27 = 16.2 and width w=4527=21.6.w = \dfrac{4}{5}\cdot 27 = 21.6.

The lit 2:12:1 region has the full width 21.621.6 and height 21.62=10.8.\dfrac{21.6}{2} = 10.8.

The two strips share the remaining height, so each has height 16.210.82=2.7.\dfrac{16.2 - 10.8}{2} = 2.7.

Thus, the correct answer is D.

Problem 14 in Other Years