2014 AMC 10A Problem 14

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Concepts:coordinate geometrymedian (geometry)triangle area

Difficulty rating: 1660

14.

The yy-intercepts, PP and Q,Q, of two perpendicular lines intersecting at the point A(6,8)A(6,8) have a sum of zero. What is the area of \triangleriangle APQ?

4545

4848

5454

6060

7272

Solution:

We have that the yy-intercepts are an equal distance from the origin since their values sum to 0.0.

Let this distance be z.z. We also have that that the distance from AA to the origin is zz since it is the median to the midpoint of the hypotenuse.

We then know that z=62+82=10 z = \sqrt{6^2 + 8^2} = 10 by the distance formula. We know the altitude from AA to PQ\overline{PQ} is 66 (it is just the xx-value of AA).

We also know that PQ=210=20,PQ = 2 \cdot 10 = 20, which tells us that the area [APQ]=12620=60. [APQ] = \dfrac{1}{2} \cdot 6 \cdot 20 = 60.

Thus, D is the correct answer.

Problem 14 in Other Years