2003 AMC 10B Problem 12

Below is the professionally curated solution for Problem 12 of the 2003 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 10B solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:system of equationsmoney

Difficulty rating: 1240

12.

Al, Betty, and Clare split $1000\$1000 among them to be invested in different ways. Each begins with a different amount. At the end of one year they have a total of $1500.\$1500. Betty and Clare have both doubled their money, whereas Al has managed to lose $100.\$100. What was Al's original portion?

$250\$250

$350\$350

$400\$400

$450\$450

$500\$500

Solution:

Let a,b,ca, b, c be the original portions. Then a+b+c=1000a+b+c=1000 and (a100)+2(b+c)=1500.(a-100)+2(b+c)=1500.

Substituting b+c=1000ab+c=1000-a into the second equation, a100+2(1000a)=1500,a-100+2(1000-a)=1500, so a=400.a=400.

Thus, the correct answer is C.

Problem 12 in Other Years