2006 AMC 8 Problem 22

Below is the professionally curated solution for Problem 22 of the 2006 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 8 solutions, or check the answer key.

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Concepts:optimization

Difficulty rating: 1610

22.

Three different one-digit positive integers are placed in the bottom row of cells. Numbers in adjacent cells are added and the sum is placed in the cell above them. In the second row, continue the same process to obtain a number in the top cell. What is the difference between the largest and smallest numbers possible in the top cell?

1616

2424

2525

2626

3535

Solution:

If the lower cells contain a,a, b,b, and c,c, the middle row will have a+ba+b and b+cb+c.

This means that the top row will have a+2b+ca+2b+c. To minimize this, put b=1b=1 in the middle and 2,32,3 in the outer cells. This yields a top number of 77.

To maximize it, put b=9b=9 in the middle and 7,87,8 in the outer cells. This yields a top number of 3333. The desired difference is 337=2633-7=26.

Thus, D is the correct answer.

Problem 22 in Other Years

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