2004 AMC 8 Problem 22

Below is the professionally curated solution for Problem 22 of the 2004 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2004 AMC 8 solutions, or check the answer key.

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Concepts:ratio and proportion

Difficulty rating: 1450

22.

At a party there are only single women and married men with their wives. The probability that a randomly selected woman is single is 25.\dfrac{2}{5}. What fraction of the people in the room are married men?

13\dfrac{1}{3}

38\dfrac{3}{8}

25\dfrac{2}{5}

512\dfrac{5}{12}

35\dfrac{3}{5}

Solution:

WLOG, let there be 55 women in the room. Then there are 525=25 \cdot \dfrac{2}{5} = 2 single women.

This means that there are 52=35 - 2 = 3 married women, which is also the number of married men.

There are a total of 5+3=85 + 3 = 8 people in the room. The fraction of married men is 38.\dfrac{3}{8}.

Thus, B is the correct answer.

Problem 22 in Other Years

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