1997 AMC 8 Problem 22

Below is the professionally curated solution for Problem 22 of the 1997 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1997 AMC 8 solutions, or check the answer key.

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Concepts:volumepower scaling of length, area, and volume

Difficulty rating: 1380

22.

A two-inch cube (2×2×2)(2\times 2\times 2) of silver weighs 33 pounds and is worth $200.\$ 200. How much is a three-inch cube of silver worth?

$300\$300

$375\$375

$450\$450

$560\$560

$675\$675

Solution:

The two-inch cube consists of 23=82^3 = 8 unit cubes. Each of these unit cubes is worth 200÷8=25 200 \div 8 = 25 dollars. To form a three-inch cube, you need 33=273^3 = 27 unit cubes. This means that it is worth 2527=675 25 \cdot 27 = 675 dollars.

Thus, E is the correct answer.

Problem 22 in Other Years

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