2020 AMC 8 第 22 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

22.

当一个正整数 NN 输入机器时,输出按下图规则计算。

例如,输入 N=7N=7 时,机器输出 37+1=223 \cdot 7 + 1 = 22。然后把输出再连续输入机器五次,最终输出为 26267221134175226 \begin{align*} &7 \to 22 \to 11 \to 34 \\ &\to 17 \to 52 \to 26 \end{align*} 对另一个起始值 NN 应用同样的 66 步过程,最终输出为 11。所有这样的整数 NN 的和是多少? N00000000001 \begin{align*} &N \to \underline{\phantom{00}} \to \underline{\phantom{00}} \to \underline{\phantom{00}}\\ &\to \underline{\phantom{00}} \to \underline{\phantom{00}} \to 1 \end{align*}

When a positive integer NN is fed into a machine, the output is a number calculated according to the rule shown below.

For example, starting with an input of N=7,N=7, the machine will output 37+1=22.3 \cdot 7 + 1 = 22. Then if the output is repeatedly inserted into the machine five more times, the final output is 26.26. 7221134175226 \begin{align*} &7 \to 22 \to 11 \to 34 \\ &\to 17 \to 52 \to 26 \end{align*} When the same 66-step process is applied to a different starting value of N,N, the final output is 1.1. What is the sum of all such integers N?N? N00000000001 \begin{align*} &N \to \underline{\phantom{00}} \to \underline{\phantom{00}} \to \underline{\phantom{00}}\\ &\to \underline{\phantom{00}} \to \underline{\phantom{00}} \to 1 \end{align*}

7373

7474

7575

8282

8383

答案:E
知识点:逆推法树状图
难度评级:1670
小提示:

从最终输出 11 倒推

Work backward from the final output 11

大提示:

前一个值总可以是 2m2m,有时也可以是 m13\frac{m-1}{3}

A previous value can be 2m2m, and sometimes m13\frac{m-1}{3}

视频讲解:
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文字解答:

11 倒推。一个值 mm 总可以由偶数输入 2m2m 产生;当 m13\frac{m-1}{3} 是正奇数时,也可以由这个奇数输入产生。

列出每次倒推后所有可能的值: {1}{2}{4}{1,8}{2,16}{4,5,32}{1,8,10,64} \begin{aligned} \{1\}&\leftarrow\{2\}\leftarrow\{4\}\leftarrow\{1,8\}\\ &\leftarrow\{2,16\}\leftarrow\{4,5,32\}\\ &\leftarrow\{1,8,10,64\}\text{。} \end{aligned} 因此可能的起始值为 118810106464,它们的和是 8383

正确答案是 E

Work backward from 1.1. A value mm can always come from the even input 2m.2m. It can also come from the odd input m13\frac{m-1}{3} when that expression is a positive odd integer.

Listing the possible values after each backward step gives {1}{2}{4}{1,8}{2,16}{4,5,32}{1,8,10,64}. \begin{aligned} \{1\}&\leftarrow\{2\}\leftarrow\{4\}\leftarrow\{1,8\}\\ &\leftarrow\{2,16\}\leftarrow\{4,5,32\}\\ &\leftarrow\{1,8,10,64\}. \end{aligned} Thus the possible starting values are 1,1, 8,8, 10,10, 64,64, whose sum is 83.83.

Thus, the correct answer is E.

第 21 题#21
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