Question

Amanda 的 $4$ 个表亲的平均年龄是 $8$ ，年龄中位数是 $5$ 。她最小和最大的两个表亲的年龄之和是多少？

The mean age of Amanda's $4$ cousins is $8,$ and their median age is $5.$ What is the sum of the ages of Amanda's youngest and oldest cousins?

$\ 13$

$\ 16$

$\ 19$

$\ 22$

$\ 25$

四个年龄的总和是 $4\cdot8=32$ 。由于中位数是 $5$ ，中间两个年龄的平均数是 $5$ ，所以它们的和是 $10$ 。

因此最小年龄与最大年龄的和为 $32-10=22$ 。

所以正确答案是 D。

The total of the four cousin ages is $4\cdot8=32$ . Since the median is $5$ , the two middle ages have average $5$ , so their sum is $10$ .

Therefore the youngest and oldest ages sum to $32-10=22$ .

Thus, the correct answer is D.