2011 AMC 10A Problem 5

Below is the professionally curated solution for Problem 5 of the 2011 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 10A solutions, or check the answer key.

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Concepts:meanratio and proportion

Difficulty rating: 1070

5.

At an elementary school, the students in third grade, fourth grade, and fifth grade run an average of 12,12, 15,15, and 1010 minutes per day, respectively. There are twice as many third graders as fourth graders, and twice as many fourth graders as fifth graders. What is the average number of minutes run per day by these students?

1212

373\dfrac{37}{3}

887\dfrac{88}{7}

1313

1414

Solution:

WLOG, let there be one fifth grader. This then tells us that there are two fourth graders and four third graders.

We can do this, since we are only interested in the average, which is not impacted by the exact number of students.

The total number of minutes the students spend running is 124+152+10=88 12 \cdot 4 + 15 \cdot 2 + 10 = 88 minutes. The total number of students is 1+2+4=7.1 + 2 + 4 = 7. The average is then 887.\dfrac{88}{7}.

Thus, C is the correct answer.

Problem 5 in Other Years