2021 AMC 10B Fall Problem 5 — Solution | LIVE by Po-Shen Loh

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2021 AMC 10B Fall Problem 5

Below is the professionally curated solution for Problem 5 of the 2021 AMC 10B Fall, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10B Fall solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:exponent power of 2

Difficulty rating: 560

5.

Let $n=8^{2022}.$ Which of the following is equal to $\frac{n}{4}?$

$4^{1010}$

$2^{2022}$

$8^{2018}$

$4^{3031}$

$4^{3032}$

Solution:

Since $8=2^3$ , we have $n=8^{2022}=2^{6066}=4^{3033}.$

Therefore $\frac n4=\frac{4^{3033}}4=4^{3032}.$

Thus, the answer is E .

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Problem 5 in Other Years

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