2015 AMC 10A Problem 3

Below is the professionally curated solution for Problem 3 of the 2015 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 10A solutions, or check the answer key.

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Concepts:arithmetic sequencepattern recognition

Difficulty rating: 960

3.

Ann made a 33-step staircase using 1818 toothpicks as shown in the figure. How many toothpicks does she need to add to complete a 55-step staircase?

99

1818

2020

2222

2424

Solution:

Let us try to find a pattern between the number of toothpicks needed for the staircases.

For a 11-step staircase, we would only need 44 toothpicks (just a square).

For a 22-step staircase, we would need 1010 toothpicks according to the diagram.

Similarly, we would need 1818 toothpicks for a 33-step staircase.

A 22-step staircase needs 104=610 - 4 = 6 more toothpicks than a 11-step staircase. A 33-step staircase needs 1810=818 - 10 = 8 more toothpicks than a 22-step staircase.

Following this pattern, we can see that a 44-step staircase will need 18+10=2818 + 10 = 28 toothpicks, and a 55-step staircase will need 28+12=4028 + 12 = 40 toothpicks.

This means that Ann would need to add 4018=2240 - 18 = 22 more toothpicks.

Thus, D is the correct answer.

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