2021 AMC 10A Spring 第 3 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

3.

两个自然数的和为 17,40217{,}402。其中一个数能被 1010 整除。如果擦去这个数的个位数字,就得到另一个数。这两个数的差是多少?

The sum of two natural numbers is 17,402.17{,}402. One of the two numbers is divisible by 10.10. If the units digit of that number is erased, the other number is obtained. What is the difference of these two numbers?

10,27210{,}272

11,70011{,}700

13,36213{,}362

14,23814{,}238

15,42615{,}426

答案:D
知识点:位值一次方程
难度评级:900
小提示:

如果删去末尾的零得到另一个数,那么较大的数是较小数的十倍。

If deleting the final zero gives the other number, the larger number is ten times the smaller one

大提示:

先用总和求出较小的那个数。

Use the sum to find the smaller number first

视频讲解:
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文字解答:

设两个数为 xxyy。不妨设 xx 能被 1010 整除,那么 xx 的个位数字是 00

擦去 xx 的个位数字,相当于把它除以 1010。题意还给出 x10=y\dfrac{x}{10} = y

由两数之和可得 x10+x=17,40211x10=17,402x=15,820 \begin{aligned} \dfrac{x}{10} + x &= 17,402 \\ \dfrac{11x}{10} &= 17,402 \\ x &= 15,820 \end{aligned}\text{。} 因此两数之差为 xx10=14,238 x - \dfrac{x}{10} = 14,238\text{。}

所以正确答案是 D

Let xx and yy be the two numbers. WLOG, let xx be divisible by 10.10. Then the units digit of xx is 0.0.

If we erase the units digit, then we are essentially dividing xx by 10.10. The problem statement also gives us that x10=y.\dfrac{x}{10} = y.

Therefore, x10+x=17,40211x10=17,402x=15,820. \begin{aligned} \dfrac{x}{10} + x &= 17,402 \\ \dfrac{11x}{10} &= 17,402 \\ x &= 15,820. \end{aligned} Then xx10=14,238. x - \dfrac{x}{10} = 14,238.

Thus, D is the correct answer.

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