2014 AMC 10B 第 6 题

先试着解答 2014 AMC 10B 第 6 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2014 AMC 10B 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

6.

Orvin 去商店时带的钱刚好够买 3030 个气球。到店后,他发现气球正在促销:按原价买 11 个气球,第二个可减价 13\frac{1}{3}。Orvin 最多可以买多少个气球?

Orvin went to the store with just enough money to buy 3030 balloons. When he arrived, he discovered that the store had a special sale on balloons: buy 11 balloon at the regular price and get a second at 13\frac{1}{3} off the regular price. What is the greatest number of balloons Orvin could buy?

3333

3434

3636

3838

3939

答案:C
知识点:比与比例钱币配对与分组
难度评级:960
解答:

假设买 1+23=531+\frac23=\frac53 个气球,其中 个按原价购买,另 个各按原价的 购买。

因此用相当于 3065=3630\cdot\frac65=36 个原价气球的钱可以买六个气球。带着买 3030 个原价气球的钱,最多可以买 个气球。

所以正确答案是 C

Each pair of balloons costs 1+23=531+\frac23=\frac53 times the regular price of one balloon.

Thus, with the money for 3030 regular-price balloons, Orvin can buy 3065=3630\cdot\frac65=36 balloons.

Thus, the correct answer is C .

← 第 5 题#5
完整试卷

其他年份的第 6 题