2014 AMC 10B 第 1 题

先试着解答 2014 AMC 10B 第 1 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2014 AMC 10B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

1.

Leah 有 1313 枚硬币,全部是一美分硬币和五美分硬币。如果她再多一枚五美分硬币,那么两种硬币的数量就相同。Leah 的硬币共值多少美分?
Leah has 1313 coins, all of which are pennies and nickels. If she had one more nickel than she has now, then she would have the same number of pennies and nickels. In cents, how much are Leah’s coins worth?
3333
3535
3737
3939
4141
答案:C
知识点:一次方程钱币
小提示:
把“再多一枚五美分硬币”转化成关于两种硬币数量的方程。
Translate the nickel condition into an equation for pennies and nickels
大提示:
求出两种硬币数量后,使用总数 1313。
Use the total of 1313 coins after finding the two counts
解答:
设一美分硬币有 pp 枚,则五美分硬币有 13−p13-p 枚;按题意,五美分硬币数也等于 p−1p-1,所以 13−p=p−113-p=p-1。因此有 77 枚一美分硬币和 66 枚五美分硬币。
硬币的总价值为 7+6⋅5=377+6\cdot 5=37 美分。
所以正确答案是 C。
Let the number of pennies be p.p. Then, the number of nickels is 13−p13-p and p−1,p-1, so 13−p=p−1.13-p=p-1. This means we have 77 pennies and 66 nickels.
Therefore, the number of cents is 7+6⋅5=37.7+6\cdot 5=37.
Thus, the correct answer is C .
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