2014 AMC 10B 第 11 题

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11.

对消费者来说,单次 n%n\% 折扣比下面任何一种折扣都更划算:

(一)连续两次 15%15\% 折扣;

(二)连续三次 10%10\% 折扣;

(三)先 25%25\% 折扣,再 5%5\% 折扣。

nn 的最小正整数值是多少?

For the consumer, a single discount of n%n\% is more advantageous than any of the following discounts:

(1) Two successive 15%15\% discounts.

(2) Three successive 10%10\% discounts.

(3) A 25%25\% discount followed by a 5%5\% discount.

What is the smallest possible positive integer value of n?n?

  27\ \ 27

 28\ 28

 29\ 29

 31\ 31

 33\ 33

答案:C
知识点:百分数不等式
难度评级:1540
解答:

三种连续折扣方案分别使顾客支付标价的 0.852=0.7225,0.93=0.729,0.75(0.95)=0.7125 \begin{aligned} 0.85^2&=0.7225,\\ 0.9^3&=0.729,\\ 0.75(0.95)&=0.7125 \end{aligned} 倍。因此它们的实际折扣分别为 27.75%27.75\%27.1%27.1\%28.75%28.75\%

单次 n%n\% 折扣必须大于这三个折扣,所以 n>28.75n>28.75。符合条件的最小正整数是 2929

所以正确答案是 C

The three successive-discount plans leave the customer paying 0.852=0.7225,0.93=0.729,0.75(0.95)=0.7125 \begin{aligned} 0.85^2&=0.7225,\\ 0.9^3&=0.729,\\ 0.75(0.95)&=0.7125 \end{aligned} times the listed price. Their effective discounts are therefore 27.75%27.75\%, 27.1%27.1\%, and 28.75%28.75\%.

A single n%n\% discount must exceed all three, so n>28.75n>28.75. The smallest positive integer that works is 2929.

Thus, the correct answer is C .

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