2001 AMC 10 Problem 11

Below is the professionally curated solution for Problem 11 of the 2001 AMC 10, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 10 solutions, or check the answer key.

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Concepts:difference of squarespattern recognition

Difficulty rating: 1070

11.

Consider the dark square in an array of unit squares, part of which is shown. The first ring of squares around this center square contains 88 unit squares. The second ring contains 1616 unit squares. If we continue this process, the number of unit squares in the 100100th ring is

396396

404404

800800

10,00010{,}000

10,40410{,}404

Solution:

The nnth ring is the border of a (2n+1)×(2n+1)(2n+1)\times(2n+1) square surrounding a (2n1)×(2n1)(2n-1)\times(2n-1) square, so it contains (2n+1)2(2n1)2=8n(2n+1)^2-(2n-1)^2=8n unit squares.

For n=100,n=100, that is 800.800. Thus, the correct answer is C.

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