2014 AMC 10A 第 10 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

10.

aa 开始的五个连续正整数的平均数为 bb。从 bb 开始的 55 个连续整数的平均数是多少?

Five positive consecutive integers starting with aa have average b.b. What is the average of 55 consecutive integers that start with b?b?

a+3a+3

a+4a+4

a+5a+5

a+6a+6

a+7a+7

答案:B
知识点:等差数列平均数
难度评级:900
解答:

xx 开始的 55 个连续整数的平均数为 5x+1+2+3+45=x+2. \dfrac{5x + 1 + 2 + 3 + 4}{5} = x + 2.

因此,从 aa 开始的 55 个连续整数的平均数为 a+2a + 2,也就是 bb

bb 开始的 55 个连续整数的平均数为 b+2=a+4.b + 2 = a + 4.

所以正确答案是 B

Note that the average of 55 consecutive numbers starting with xx is 5x+1+2+3+45=x+2. \dfrac{5x + 1 + 2 + 3 + 4}{5} = x + 2.

This means that the average of 55 consecutive integers starting with aa is a+2,a + 2, which we know is b.b.

Furthermore, the average of 55 consecutive numbers starting with bb is b+2=a+4.b + 2 = a + 4.

Thus, B is the correct answer.

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