Question

一月的某一天，内布拉斯加州 Lincoln 的最高气温比最低气温高 $16$ 度，且最高气温和最低气温的平均值为 $3$ 度。那天 Lincoln 的最低气温是多少度？

On a particular January day, the high temperature in Lincoln, Nebraska, was $16$ degrees higher than the low temperature, and the average of the high and low temperatures was $3$ degrees. What was the low temperature in Lincoln that day (in degrees)?

$-13$

$-8$

$-5$

$-3$

$11$

答案：C

知识点：平均数一次方程

难度评级：560

解答：

设最低气温为 $l$ 。则最高气温为 $l+16$ 。

平均值满足因此 $l = -5$ 。 $\dfrac{l+l+16}2 = l+8 = 3.$

所以正确答案是 C。

Let the low temperature be represented by $l.$ Then, the high temperature is $l+16.$

This makes the average $\dfrac{l+l+16}2 = l+8 = 3.$ Therefore, $l = -5.$

Thus, the correct answer is C .

2013 AMC 10B 第 3 题

答案：C

难度评级：560

解答：

其他年份的第 3 题