2011 AMC 10B Problem 19

Below is the professionally curated solution for Problem 19 of the 2011 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 10B solutions, or check the answer key.

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Concepts:radicalabsolute valuequadratic

Difficulty rating: 1580

19.

What is the product of all the roots of the equation 5x+8=x216?\sqrt{5 | x | + 8} = \sqrt{x^2 - 16}?

64-64

24-24

9-9

2424

576576

Solution:

The equation is equal to 5x+8=x216.\sqrt{5 | x | + 8} = \sqrt{|x|^2 - 16}. Solving, we get that: 5x+8=x216x25x24=0(x8)(x+3)=0\begin{align*} 5|x|+8 &= |x|^2-16 \\ |x|^2-5|x|-24&=0 \\ (|x|-8)(|x|+3)&=0 \end{align*} This makes x=3,8,|x|=-3,8, making x=8|x|=8 the only possible value. Thus, x=8,8x =8,-8 with a product of 64.-64.

Thus, the correct answer is A .

Problem 19 in Other Years