2005 AMC 10B 第 11 题

先试着解答 2005 AMC 10B 第 11 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2005 AMC 10B 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

11.

一个数列的第一项为 20052005。之后每一项都等于前一项各位数字的立方和。这个数列的第 20052005 项是多少?
The first term of a sequence is 2005.2005. Each succeeding term is the sum of the cubes of the digits of the previous term. What is the 20052005th term of the sequence?
2929
5555
8585
133133
250250
答案:E
知识点:递推数字找规律
小提示:
先计算前几项,直到数值开始重复。
Compute the first several terms until the values start repeating
大提示:
找出循环后,将第一项之后的步数除以循环长度并取余。
Once you find the repeating cycle, reduce the number of steps after the first term modulo its length
解答:
数列开头是 2005,133,55,250,133,…2005, 133, 55, 250, 133, \ldots,所以从第一项以后,它重复循环 133,55,250133, 55, 250,其长度为 33。
第 22、33 和 44 项分别是这个循环的第一、第二和第三项。因为 2005−2=20032005 - 2 = 2003 除以 33 的余数是 22,所以第 20052005 项对应循环的第三项,即 250250。
所以正确答案是 E。
The sequence begins 2005,133,55,250,133,…,2005, 133, 55, 250, 133, \ldots, so after the first term it repeats the cycle 133,55,250133, 55, 250 of length 3.3.
Terms 2,2, 3,3, and 44 are the first, second, and third entries of this cycle. Because 2005−2=20032005 - 2 = 2003 leaves remainder 22 upon division by 3,3, the 20052005th term matches the third entry, 250.250.
Thus, E is the correct answer.
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