2023 AMC 8 第 22 题

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22.

在一个正整数序列中,从第三项开始,每一项都是前两项的乘积。该序列的第六项是 40004000。第一项是多少?

In a sequence of positive integers, each term after the second is the product of the previous two terms. The sixth term in the sequence is 4000.4000. What is the first term?

11

22

44

55

1010

答案:D
知识点:递推质因数分解
难度评级:1790
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文字解答:

设第一项为 xx,第二项为 yy

序列前几项为 因此 x3y5=4000x^3y^5 = 4000x,y,xy,xy2,x2y3,x3y5, x, y, xy, xy^2, x^2y^3, x^3y^5, \cdots

分解 40004000: 因为 xxyy 是正整数,40004000 中可能作为五次方的因子只有 1132324000=2553. 4000 = 2^5 \cdot 5^3.

y=1y = 1,则 x3=4000x^3 = 4000,但 40004000 不是完全立方数。因此 y5=32 y^5 = 32 y=2. y = 2.

这迫使 xx 等于 55

正确答案是 D

Let xx be the first term and yy be the second.

Then we get the following sequence. x,y,xy,xy2,x2y3,x3y5, x, y, xy, xy^2, x^2y^3, x^3y^5, \cdots From this, we get that x3y5=4000.x^3y^5 = 4000.

Factoring 4000,4000, we get 4000=2553. 4000 = 2^5 \cdot 5^3. We need xx and yy to be integers. The only fifth powers that divides 40004000 are 11 and 32.32.

If y=1,y = 1, then x3=4000,x^3 = 4000, which doesn't work since 40004000 is not a perfect cube. Therefore, y5=32 y^5 = 32 y=2. y = 2.

This forces xx to equal 5.5.

Thus, D is the correct answer.

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