Solution:

Since we are working with angles and reflections, working with polar coordinates would make this problem easier to deal with.

Let $(r, \theta)$ be a polar coordinate. Rotating this by $k$ degrees counterclockwise maps the point to $(r, \theta + k^{\circ})$ and then reflecting it maps it to $(r, 180 - \theta - k^{\circ}.)$

Therefore, we have that $$T_k(r, \theta) = (r, 180 - \theta - k^{\circ}).$$

From this, we can see that $$T_{k + 1}(T_k(r, \theta)) =$$$$T_{k + 1}(r, 180^{\circ} - \theta - k^{\circ}) =$$$$(r, \theta - 1^{\circ}).$$

Now, let's analyze what happens to the point $(1, 0^{\circ}).$

After $T_1,$ we get $(1, 179^{\circ}).$

After $T_2,$ we get $(1, -1^{\circ}).$

After $T_3,$ we get $(1, 178^{\circ}).$

After $T_4,$ we get $(1, -2^{\circ}).$

$$\vdots$$

After $T_{2n - 1},$ we get $(1, 180^{\circ} - k^{\circ}).$

After $T_{2n},$ we get $(1, -k^{\circ}).$

From this, we can see that the first time the angle is back to $0^{\circ}$ is when $n = 180$ and $k = 359.$

Thus, A is the correct answer.