2021 AMC 10A Fall 第 6 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

6.

鸸鹋 Elmer 在乡村道路上相邻两根电线杆之间行走需要 4444 个等长步幅。鸵鸟 Oscar 用 1212 个等长跃步可以走完同一距离。电线杆等距排列,沿这条路第 4141 根电线杆与第一根电线杆的距离正好是一英里,即 52805280 英尺。Oscar 的一次跃步比 Elmer 的一步长多少英尺?

Elmer the emu takes 4444 equal strides to walk between consecutive telephone poles on a rural road. Oscar the ostrich can cover the same distance in 1212 equal leaps. The telephone poles are evenly spaced, and the 4141st pole along this road is exactly one mile (52805280 feet) from the first pole. How much longer, in feet, is Oscar's leap than Elmer's stride?

66

88

1010

1111

1515

答案:B
知识点:比与比例单位换算植树问题
难度评级:870
解答:

11 根和第 4141 根之间有 4040 个间隔,所以相邻电线杆之间距离为 英尺。 5280÷40=132 5280 \div 40 = 132

这说明 Elmer 的一步长为 英尺。类似地,Oscar 的一步长为 英尺。因此 Oscar 的跃步长 113=811 - 3 = 8 英尺。 132÷44=3 132 \div 44 = 3 132÷12=11 132 \div 12 = 11

所以正确答案是 B

There are 4040 gaps between the 11st and 4141st pole, which means that the distance between consecutive poles is 5280÷40=132 5280 \div 40 = 132 feet.

This means that each of Elmer's strides is 132÷44=3 132 \div 44 = 3 feet. Similarly, each of Oscar's leaps is 132÷12=11 132 \div 12 = 11 feet. This makes Oscar's leap 113=811 - 3 = 8 feet longer.

Thus, B is the correct answer.

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