2020 AMC 10B 第 11 题

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11.

Carr 老师要求学生阅读书单上 1010 本书中的任意 55 本。Harold 从书单中随机选 55 本,Betty 也随机选五本。他们恰好有 22 本书都选中的概率是多少?

Ms. Carr asks her students to read any 55 of the 1010 books on a reading list. Harold randomly selects 55 books from this list, and Betty does the same. What is the probability that there are exactly 22 books that they both select?

18\dfrac{1}{8}

536\dfrac{5}{36}

1445\dfrac{14}{45}

2563\dfrac{25}{63}

12\dfrac{1}{2}

答案:D
知识点:组合基本概率
难度评级:1140
解答:

固定 Harold 选的 55 本书。Betty 从这五本中恰好选两本有 (52)\binom{5}{2} 种方式,另外三本从 Harold 没选的 55 本中选,有 (53)\binom{5}{3} 种方式。

因此 Betty 恰好选中 Harold 书单中两本、书单外三本的方式数为 (52)(53)=100\binom{5}{2}\binom{5}{3}=100。 Betty 任意选择五本书共有 (105)=252\binom{10}{5}=252 种方式,其中有利选择有 种,所以所求概率为 所以正确答案是 D100252=2563.\frac{100}{252}=\frac{25}{63}.

Assume that Harold has already picked his 55 books. Of these five books, there are (52)\binom{5}{2} ways that Betty can have picked exactly two of the same books as Harold, and (53)\binom{5}{3} ways that Betty can choose her other three books from the 55 books not on Harold's list.

Thus there are (52)(53)=100\binom{5}{2}\binom{5}{3}=100 favorable choices for Betty out of (105)=252\binom{10}{5}=252 equally likely choices. The probability is 100252=2563.\frac{100}{252}=\frac{25}{63}. Thus, D is the correct answer.

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