2017 AMC 10A 第 12 题
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12.
设 是坐标平面中的点 的集合,满足三个量 、 中有两个相等,而第三个量不大于这个公共值。下面哪一项正确描述了 ?
Let be a set of points in the coordinate plane such that two of the three quantities and are equal and the third of the three quantities is no greater than this common value. Which of the following is a correct description of
一个点
a single point
两条相交直线
two intersecting lines
三条直线,且两两交于三个不同点
three lines whose pairwise intersections are three distinct points
一个三角形
a triangle
有共同端点的三条射线
three rays with a common endpoint
答案:E
解答:
分情况讨论哪两个量相等。若 ,则 。这还给出 这是一条以 为端点、沿负 方向延伸的射线。
类似地,若 ,则 ,并且 这也是一条以 为端点、但沿负 方向延伸的射线。
最后,若 ,则直线为 。此外有 且 注意,由等式可知满足其中一个条件时,另一个也必然满足。
当 时,。其余点在线上,满足 且 。
这描述了另一条从 出发、沿第三个方向延伸的射线。
三种情形都得到从 出发、方向各不相同的射线。
所以正确答案是 E。
Let us case on which of the values are equal. If then This also tells us that This describes a ray starting at and extending in the negative direction.
Similarly, if then and This also describes a ray starting at but instead extending in the negative direction.
Finally, if then we have the line Furthermore, we have that and Note that if one of these conditions is met, the other is also necessarily true due to the equation of the line.
If then The other points are along the line, where and
This describes another ray that starts at and goes off in some third direction.
All three cases result in rays originating from that all go in different directions.
Thus, E is the correct answer.
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