2015 AMC 10B 第 15 题

先试着解答 2015 AMC 10B 第 15 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2015 AMC 10B 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

15.

Hamlet 镇中,每一匹马对应 33 个人;每一头牛对应 44 只羊;每一个人对应 33 只鸭。下列哪个数不可能是 Hamlet 镇中人、马、羊、牛、鸭的总数?

The town of Hamlet has 33 people for each horse, 44 sheep for each cow, and 33 ducks for each person. Which of the following could not possibly be the total number of people, horses, sheep, cows, and ducks in Hamlet?

4141

4747

5959

6161

6666

答案:B
知识点:丢番图方程模运算
难度评级:1420
解答:

若有 hh 匹马和 cc 头牛,则有 3h3h 个人、9h9h 只鸭和 4c4c 只羊,总数为 13h+5c13h+5c

4747 外,其余选项都可表示为所需形式: 对 4747,减去 0,13,26,390,13,26,39 后分别得到 47,34,21,847,34,21,8,没有一个是 55 的倍数。 41=132+53,59=133+54,61=132+57,66=132+58. \begin{gathered} 41=13\cdot2+5\cdot3, \\ 59=13\cdot3+5\cdot4, \\ 61=13\cdot2+5\cdot7, \\ 66=13\cdot2+5\cdot8. \end{gathered}

所以正确答案是 B

If there are hh horses and cc cows, then there are 3h3h people, 9h9h ducks, and 4c4c sheep. The total is therefore 13h+5c13h+5c.

The listed values except 4747 can be written in that form: 41=132+53,59=133+54,61=132+57,66=132+58. \begin{gathered} 41=13\cdot2+5\cdot3, \\ 59=13\cdot3+5\cdot4, \\ 61=13\cdot2+5\cdot7, \\ 66=13\cdot2+5\cdot8. \end{gathered} For 4747, subtracting 0,13,26,390,13,26,39 leaves 47,34,21,847,34,21,8, none of which is divisible by 55.

Thus, the correct answer is B.

← 第 14 题#14
完整试卷

其他年份的第 15 题