2013 AMC 10B 第 5 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

5.

正整数 aabb 都小于 66。表达式 的最小可能值是多少? 2aab?2 \cdot a - a \cdot b?

Positive integers aa and bb are each less than 6.6. What is the smallest possible value for 2aab?2 \cdot a - a \cdot b?

20-20

15-15

10-10

00

22

答案:B
知识点:因式分解最优化
难度评级:870
解答:

2aab=a(2b)2a-ab=a(2-b)

为了使它最小,取 bb 尽可能大,使 2b2-b 最负,同时取 aa 尽可能大。因为 a,b<6a,b<6,可取 a=b=5a=b=5

此时 5(25)=155(2-5)=-15

所以正确答案是 B

The expression is 2aab=a(2b)2a-ab=a(2-b).

To make it as small as possible, choose bb as large as possible so that 2b2-b is most negative, and choose aa as large as possible. Since a,b<6a,b<6, take a=b=5a=b=5.

The minimum value is 5(25)=155(2-5)=-15.

Thus, the correct answer is B .

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