2011 AMC 10B 第 11 题

先试着解答 2011 AMC 10B 第 11 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2011 AMC 10B 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

11.

一个房间里有 5252 人。使“这个房间中至少有 nn 人的生日在同一个月份”这一陈述总为真的最大 nn 是多少?

There are 5252 people in a room. What is the largest value of nn such that the statement "At least nn people in this room have birthdays falling in the same month" is always true?

22

33

44

55

1212

答案:D
知识点:抽屉原理
难度评级:1070
解答:

n6n\geq 6 不一定成立,因为可以让前 44 个月各有 55 人生日,其余八个月各有 44 人生日。

但一定有某个月至少 55 人生日,因为平均每月人数为 5212\frac{52}{12},大于 44

所以正确答案是 D

It isn't necessarily true for n6n\geq 6 as we could have 55 people born in the first 44 months and 44 people born in the subsequent months.

However, one month must be greater than or equal to 55 as the average of the number of people born in each month is 5212\frac{52}{12} which is greater than 4,4, and some month must be above average.

Thus, the correct answer is D .

← 第 10 题#10
完整试卷

其他年份的第 11 题