2011 AMC 10A 第 6 题

先试着解答 2011 AMC 10A 第 6 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2011 AMC 10A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

6.

集合 AA 有 2020 个元素,集合 BB 有 1515 个元素。A∪BA \cup B,即 AA 和 BB 的并集,最少可能有多少个元素?
Set AA has 2020 elements, and set BB has 1515 elements. What is the smallest possible number of elements in A∪B,A \cup B, the union of AA and B?B?
55
1515
2020
3535
300300
答案:C
知识点:韦恩图极限情形界定
小提示:
并集必须包含较大集合的所有元素。
The union must contain all elements of the larger set
大提示:
让 BB 成为 AA 的子集可使并集最小。
Make BB a subset of AA to minimize the union
解答:
要使并集元素数最少,就要让两个集合重叠尽可能多。
可以让 BB 完全包含于 AA,此时并集就是 AA,共有 2020 个元素。
所以正确答案是 C。
To minimize the number of elements in the union, we want to maximize the overlap between the two sets.
We can then assume that BB is contained completely within A,A, which means that the union is the same as A,A, which has 2020 elements.
Thus, C is the correct answer.
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