2009 AMC 10A 第 20 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

20.

Andrea 和 Lauren 相距 2020 千米。她们骑自行车相向而行,其中 Andrea 的速度是 Lauren 的三倍,两人之间的距离以每分钟 11 千米的速度缩短。55 分钟后,Andrea 因爆胎停止骑行并等待 Lauren。从她们开始骑车算起,Lauren 过多少分钟到达 Andrea 所在位置?

Andrea and Lauren are 2020 kilometers apart. They bike toward one another with Andrea traveling three times as fast as Lauren, and the distance between them decreasing at a rate of 11 kilometer per minute. After 55 minutes, Andrea stops biking because of a flat tire and waits for Lauren. After how many minutes from the time they started to bike does Lauren reach Andrea?

2020

3030

5555

6565

8080

答案:D
知识点:路程、速度与时间速率
难度评级:1510
解答:

设 Lauren 的速度为 rr 千米/分钟。则 r+3r=1r + 3r = 1,所以 r=14r = \dfrac14

55 分钟间距缩短 55 千米,还剩 1515 千米。Lauren 独自以 14\dfrac14 千米/分钟走完,需 151/4=60\dfrac{15}{1/4} = 60 分钟。

总时间为 5+60=655 + 60 = 65 分钟。

所以正确答案是 D

Let Lauren's rate be rr km/min. Then r+3r=1,r + 3r = 1, so r=14.r = \dfrac14.

In the first 55 minutes the gap shrinks by 55 km, leaving 1515 km. Lauren covers this alone at 14\dfrac14 km/min, taking 151/4=60\dfrac{15}{1/4} = 60 minutes.

The total time is 5+60=655 + 60 = 65 minutes.

Thus, the correct answer is D.

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