2008 AMC 10A 第 12 题

先试着解答 2008 AMC 10A 第 12 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2008 AMC 10A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

12.

在一堆红、蓝、绿三色弹珠中,红弹珠比蓝弹珠多 25%25\%,绿弹珠比红弹珠多 60%60\%。设红弹珠有 rr 个。这堆弹珠总数是多少?
In a collection of red, blue, and green marbles, there are 25%25\% more red marbles than blue marbles, and there are 60%60\% more green marbles than red marbles. Suppose that there are rr red marbles. What is the total number of marbles in the collection?
2.85r2.85r
3r3r
3.4r3.4r
3.85r3.85r
4.25r4.25r
答案:C
知识点:百分数代数变形
小提示:
用 rr 表示蓝弹珠和绿弹珠数量。
Write the blue and green counts in terms of rr
大提示:
由 r=1.25br = 1.25b 得 b=0.8rb = 0.8r,且 g=1.6rg = 1.6r。
From r=1.25br = 1.25b we get b=0.8r,b = 0.8r, and g=1.6rg = 1.6r
解答:
因为 r=1.25br = 1.25b,蓝弹珠数为 b=r1.25=0.8rb = \dfrac{r}{1.25} = 0.8r。
绿弹珠数为 g=1.6rg = 1.6r。
总数为 r+0.8r+1.6r=3.4rr + 0.8r + 1.6r = 3.4r。
所以正确答案是 C。
Since r=1.25b,r = 1.25b, the number of blue marbles is b=r1.25=0.8r.b = \dfrac{r}{1.25} = 0.8r.
The number of green marbles is g=1.6r.g = 1.6r.
The total is r+0.8r+1.6r=3.4r.r + 0.8r + 1.6r = 3.4r.
Thus, the correct answer is C.
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