2007 AMC 10B 第 9 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

9.

一个密码编码规则如下:某个字母在给定消息中第一次出现时,替换成字母表中向右 11 位的字母(规定 A 在 Z 的右边一位)。同一个字母第二次出现时,替换成向右 1+21+2 位的字母;第三次出现时,替换成向右 1+2+31+2+3 位的字母;依此类推。

例如,用这种编码,单词“banana”变为“cbodqg”。在消息“Lee's sis is a Mississippi miss, Chriss!”中,最后一个字母 s 会被替换成什么字母?

A cryptographic code is designed as follows. The first time a letter appears in a given message it is replaced by the letter that is 11 place to its right in the alphabet (assuming that the letter A is one place to the right of the letter Z). The second time this same letter appears in the given message, it is replaced by the letter that is 1+21+2 places to the right, the third time it is replaced by the letter that is 1+2+31+2+3 places to the right, and so on. For example, with this code the word "banana" becomes "cbodqg". What letter will replace the last letter s in the message

"Lee's sis is a Mississippi miss, Chriss!"?

gg

hh

oo

ss

tt

答案:D
知识点:模运算三角形数
难度评级:1370
解答:

最后一个 s 是消息中字母 s 的第 1212 次出现,所以它向右移动 1+2++12=12132=781+2+\cdots+12=\dfrac{12\cdot 13}{2}=78 位。

因为 78=32678=3\cdot 26 是字母表长度 2626 的倍数,所以移动后回到同一个字母 s。

所以正确答案是 D

The final s is the 1212th appearance of the letter s in the message, so it is shifted 1+2++12=12132=781+2+\cdots+12=\dfrac{12\cdot 13}{2}=78 places to the right.

Since 78=32678=3\cdot 26 is a multiple of the alphabet length 26,26, the shift returns to the same letter, s.

Thus, the correct answer is D.

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