2021 AMC 10B Fall Problem 9

Below is the professionally curated solution for Problem 9 of the 2021 AMC 10B Fall, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10B Fall solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:weighted meanratio and proportionfractionlinear equation

Difficulty rating: 1280

9.

The knights in a certain kingdom come in two colors. 27\frac{2}{7} of them are red, and the rest are blue. Furthermore, 16\frac{1}{6} of the knights are magical, and the fraction of red knights who are magical is 22 times the fraction of blue knights who are magical. What fraction of red knights are magical?

29 \dfrac{2}{9}

313 \dfrac{3}{13}

727 \dfrac{7}{27}

27 \dfrac{2}{7}

13 \dfrac{1}{3}

Solution:

Let xx be the fraction of blue knights who are magical. Then the fraction of red knights who are magical is 2x2x.

The total magical fraction is a weighted average over the red and blue groups: 27(2x)+57(x)=16.\frac27(2x)+\frac57(x)=\frac16.

Thus 97x=16\frac97x=\frac16, so x=754x=\frac7{54}. The red magical fraction is 2x=7272x=\frac7{27}.

Thus, the answer is C .

Problem 9 in Other Years