2005 AMC 10A 第 11 题

先试着解答 2005 AMC 10A 第 11 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2005 AMC 10A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

11.

一个边长为 nn 个单位的木质立方体六个面全部涂红,然后切成 n3n^3 个单位小立方体。所有小立方体面的总数中,正好有四分之一是红色的。nn 是多少?
A wooden cube nn units on a side is painted red on all six faces and then cut into n3n^3 unit cubes. Exactly one-fourth of the total number of faces of the unit cubes are red. What is n?n?
33
44
55
66
77
答案:B
知识点:正方体表面积比与比例
小提示:
n3n^3 个单位立方体每个都有 66 个面,所以总面数为 6n36n^3。
Each of the n3n^3 unit cubes has 66 faces, so there are 6n36n^3 faces in all
大提示:
只有原立方体表面是红色的,贡献 6n26n^2 个红色面;令 6n26n3=14\dfrac{6n^2}{6n^3} = \dfrac{1}{4}。
Only the original surface is red, contributing 6n26n^2 red faces; set 6n26n3=14\dfrac{6n^2}{6n^3} = \dfrac{1}{4}
解答:
小立方体共有 6n36n^3 个面,其中来自原立方体外表面的红色面共有 6n26n^2 个。因此 6n26n3=1n=14\dfrac{6n^2}{6n^3} = \dfrac{1}{n} = \dfrac{1}{4},所以 n=4n = 4。
所以正确答案是 B。
The unit cubes have 6n36n^3 faces total, of which the original surface accounts for 6n26n^2 red faces. Then 6n26n3=1n=14,\dfrac{6n^2}{6n^3} = \dfrac{1}{n} = \dfrac{1}{4}, so n=4.n = 4.
Thus, the correct answer is B.
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