2004 AMC 10A 第 12 题

先试着解答 2004 AMC 10A 第 12 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2004 AMC 10A 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

12.

Henry’s Hamburger Heaven 提供以下汉堡配料:番茄酱、芥末酱、蛋黄酱、番茄、生菜、腌黄瓜、奶酪和洋葱。顾客可以选择一块、两块或三块肉饼,并可选择任意一组配料。共有多少种不同的汉堡可以点?
Henry’s Hamburger Heaven offers its hamburgers with the following condiments: ketchup, mustard, mayonnaise, tomato, lettuce, pickles, cheese, and onions. A customer can choose one, two, or three meat patties, and any collection of condiments. How many different kinds of hamburgers can be ordered?
2424
256256
768768
40,32040{,}320
120,960120{,}960
答案:C
知识点:乘法原理子集
小提示:
88 种配料中每一种都可以选择或不选择。
Each of the 88 condiments is independently included or left out
大提示:
将 282^8 种配料选择乘以 33 种肉饼数量选择。
Multiply the 282^8 condiment choices by the 33 choices of patty count
解答:
88 种配料各自独立选择是否加入,共有 28=2562^8 = 256 种配料组合。
每种组合还有 33 种肉饼数量选择,所以汉堡种类为 3×256=768。 3 \times 256 = 768\text{。}
所以正确答案是 C。
Each of the 88 condiments is independently in or out, giving 28=2562^8 = 256 condiment combinations.
For each of these there are 33 choices of patty count, so the number of hamburgers is 3×256=768. 3 \times 256 = 768.
Thus, the correct answer is C.
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