2001 AMC 10 第 15 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

15.

一条街的两侧路缘平行,相距 4040 英尺。一条由两条平行条纹围成的人行横道斜穿过街道。两条条纹在路缘上截出的长度为 1515 英尺,每条条纹长 5050 英尺。求两条条纹之间的距离,单位为英尺。

A street has parallel curbs 4040 feet apart. A crosswalk bounded by two parallel stripes crosses the street at an angle. The length of the curb between the stripes is 1515 feet and each stripe is 5050 feet long. Find the distance, in feet, between the stripes.

99

1010

1212

1515

2525

答案:C
知识点:平行四边形面积
难度评级:1410
解答:

人行横道是一个平行四边形。以路缘上的 1515 英尺为底、街道宽 4040 英尺为高,其面积为 1540=60015\cdot40=600

以一条 5050 英尺的条纹为底,面积等于 5050 乘以两条条纹之间的距离 dd,所以 d=600/50=12d=600/50=12

所以正确答案是 C

The crosswalk is a parallelogram. Using the curb (1515 ft) as base and the street width (4040 ft) as height, its area is 1540=60015\cdot40=600 square feet.

Using a stripe (5050 ft) as base, the area equals 5050 times the distance dd between the stripes, so d=600/50=12.d=600/50=12.

Thus, the correct answer is C.

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