2000 AMC 10 Problem 25

Below is the professionally curated solution for Problem 25 of the 2000 AMC 10, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 10 solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:date and timemodular arithmetic

Difficulty rating: 1860

25.

In year N,N, the 300300th day of the year is a Tuesday. In year N+1,N + 1, the 200200th day is also a Tuesday. On what day of the week did the 100100th day of year N1N - 1 occur?

Thursday

Friday

Saturday

Sunday

Monday

Solution:

From day 300300 of year NN to day 200200 of year N+1N + 1 is (L300)+200(L - 300) + 200 days, where LL is the length of year N.N. If NN were not a leap year, this is 2656(mod7),265 \equiv 6 \pmod 7, giving a Monday, not a Tuesday. So year NN is a leap year, and the count is 266=738,266 = 7 \cdot 38, consistent with Tuesday.

Then years N1N - 1 and N+1N + 1 are not leap years.

The 100100th day of year N1N - 1 precedes the Tuesday (day 300300 of year NN) by (365100)+300=565(365 - 100) + 300 = 565 days. Since 565=780+5,565 = 7 \cdot 80 + 5, that day is 55 days earlier in the week than Tuesday, which is a Thursday.

Thus, the correct answer is A.

Problem 25 in Other Years