2021 AMC 10B Fall 第 8 题

先试着解答 2021 AMC 10B Fall 第 8 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 2021 AMC 10B Fall 解答,或核对答案

所有题目均经美国数学协会(MAA)官方合法授权使用。

8.

16,38416,384 的最大质因数是 22,因为 16,384=21416,384 = 2^{14}。求 16,38316,383 的最大质因数的各位数字之和。

The greatest prime number that is a divisor of 16,38416,384 is 22 because 16,384=214.16,384 = 2^{14}. What is the sum of the digits of the greatest prime number that is a divisor of 16,383?16,383?

33

77

1010

1616

2222

答案:C
知识点:质因数分解平方差
难度评级:1030
解答:

有 因为 129=343129=3\cdot 43,所以 因此 127127 是最大质因数,其各位数字之和为 101016,383=163841=2141=(271)(27+1)=127129.\begin{aligned}16,383 &= 16384-1 \\&= 2^{14}-1 \\&= (2^7-1)(2^7+1) \\&= 127\cdot 129.\end{aligned} 16383=343127.16383 = 3\cdot 43\cdot 127.

所以答案是 C

We know 16,383=163841=2141=(271)(27+1)=127129.\begin{aligned}16,383 &= 16384-1 \\&= 2^{14}-1 \\&= (2^7-1)(2^7+1) \\&= 127\cdot 129.\end{aligned} Since 129=343,129=3\cdot 43, we get 16383=343127.16383 = 3\cdot 43\cdot 127. Therefore, 127127 is the largest prime factor, and the sum of its digits is 10.10.

Thus, the answer is C .

← 第 7 题#7
完整试卷

其他年份的第 8 题