2019 AMC 10A 第 1 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

1.

求下式的值: 2(0(19))+((20)1)9?2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9?

What is the value of 2(0(19))+((20)1)9?2^{\left(0^{\left(1^9\right)}\right)}+\left(\left(2^0\right)^1\right)^9?

00

11

22

33

44

答案:C
知识点:指数运算顺序
难度评级:560
解答:

2(0(19))+((20)1)9=201+(11)9=20+19=2. \begin{aligned} &2^{\left(0^{\left(1^9\right)}\right)}\\ &\quad+\left(\left(2^0\right)^1\right)^9\\ &=2^{0^1}+(1^1)^9\\ &=2^0+1^9\\ &=2. \end{aligned}

所以正确答案是 C

We can evaluate from the top of each exponent tower downward: 2(0(19))+((20)1)9=201+(11)9=20+19=2. \begin{aligned} &2^{\left(0^{\left(1^9\right)}\right)}\\ &\quad+\left(\left(2^0\right)^1\right)^9\\ &=2^{0^1}+(1^1)^9\\ &=2^0+1^9\\ &=2. \end{aligned}

Thus, C is the correct answer.

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