2016 AMC 10B 第 7 题

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7.

两个锐角的度数之比为 5:45:4,且其中一个角的余角是另一个角的余角的两倍。这两个角的度数之和是多少?

The ratio of the measures of two acute angles is 5:4,5:4, and the complement of one of these two angles is twice as large as the complement of the other. What is the sum of the degree measures of the two angles?

 75\ 75

 90\ 90

 135\ 135

 150\ 150

 270\ 270

答案:C
知识点:比与比例一次方程
难度评级:1070
解答:

设较小角为 xx。则较大角为 54x\frac 54 x,两角和为 94x\frac 94 x

它们的余角分别是 90x90-x9054x90 - \frac 54x。由于 90x90-x 大于 9054x90-\frac 54 x,所以 90x=2(9054x)90x=18052xx=60.\begin{aligned}90 -x &= 2\left(90 - \frac 54 x\right) \\90-x&= 180-\frac 52 x\\x&=60.\end{aligned}

因此两角和为 9460=135.\dfrac 94 \cdot 60=135.

所以正确答案是 C

Let the smaller angle be x.x. Then, the larger angle is 54x.\frac 54 x. Note that their sum is 94x.\frac 94 x.

Their complements are then 90x90-x and 9054x.90 - \frac 54x. Since 90x90-x is larger than 9054x,90-\frac 54 x, we know 90x=2(9054x)90x=18052xx=60.\begin{aligned}90 -x &= 2\left(90 - \frac 54 x\right) \\90-x&= 180-\frac 52 x\\x&=60.\end{aligned}

Therefore, the sum is 9460=135.\dfrac 94 \cdot 60=135.

Thus, the correct answer is C .

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