2013 AMC 10A 第 6 题

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所有题目均经美国数学协会(MAA)官方合法授权使用。

6.

Joey 和他的五个兄弟年龄分别为 3355779911111313。一天下午,两个年龄和为 1616 的兄弟去看电影,两个小于 1010 岁的兄弟去打棒球,Joey 和 55 岁的兄弟留在家里。Joey 几岁?

Joey and his five brothers are ages 3,3, 5,5, 7,7, 9,9, 11,11, and 13.13. One afternoon two of his brothers whose ages sum to 1616 went to the movies, two brothers younger than 1010 went to play baseball, and Joey and the 55-year-old stayed home. How old is Joey?

33

77

99

1111

1313

答案:D
知识点:逻辑推理分类讨论
难度评级:1140
解答:

年龄和为 1616 的配对有 (3,13)(3,13)(5,11)(5,11)(7,9)(7,9)

55 岁的人留在家里,所以看电影的不能是 (5,11)(5,11)。若 77 岁和 99 岁的兄弟去看电影,则剩下小于 1010 岁的只有 33 岁的兄弟,不够两人去打棒球。

因此看电影的是 (3,13)(3,13),打棒球的是 (7,9)(7,9),剩下的 Joey 是 1111 岁。

所以正确答案是 D

The age pairs that sum to 1616 are (3,13)(3,13), (5,11)(5,11), and (7,9)(7,9).

The 55-year-old stayed home, so the movie pair cannot be (5,11)(5,11). If 77 and 99 went to the movies, then the only remaining brother younger than 1010 would be the 33-year-old, not enough for baseball.

Thus the movie pair was (3,13)(3,13), the baseball pair was (7,9)(7,9), and Joey is the remaining brother, age 1111.

Thus, D is the correct answer.

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