2010 AMC 10B 第 6 题

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6.

圆心为 OOAB\overline{AB} 是直径,点 CC 在圆上,且 COB=50\angle COB = 50^\circCAB\angle CAB 的度数是多少?

A circle is centered at O,O, AB\overline{AB} is a diameter and CC is a point on the circle with COB=50.\angle COB = 50^\circ. What is the degree measure of CAB?\angle CAB?

2020

2525

4545

5050

6565

答案:B
知识点:等腰三角形导角
难度评级:960
解答:

参考下图:

由于直径的两端与圆心在同一直线上, AOC=18050=130. \angle AOC = 180^{\circ} - 50^{\circ} = 130^{\circ}.

AOC\triangle AOC 是等腰三角形,所以 CAO=1801302=25. \angle CAO = \dfrac{180^{\circ} - 130^{\circ}}{2} = 25^{\circ}.

因为 CAB=CAO\angle CAB = \angle CAO,所以 CAB=25\angle CAB = 25^{\circ}

所以正确答案是 B

Consider the following diagram:

We have that AOC=18050=130. \angle AOC = 180^{\circ} - 50^{\circ} = 130^{\circ}.

Since AOC\triangle AOC is isosceles, we have that CAO=1801302=25. \angle CAO = \dfrac{180^{\circ} - 130^{\circ}}{2} = 25^{\circ}.

Since CAB=CAO,\angle CAB = \angle CAO, we have that CAB=25.\angle CAB = 25^{\circ}.

Thus, B is the correct answer.

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