2022 AMC 10A 第 6 题

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6.

a<0a < 0 时,下列表达式等于 中的哪一个? a2(a1)2\left|a-2-\sqrt{(a-1)^2}\right|

Which expression is equal to a2(a1)2\left|a-2-\sqrt{(a-1)^2}\right| for a<0?a < 0?

32a3 - 2a

1a1 - a

11

a+1a + 1

33

答案:A
知识点:绝对值根式
难度评级:900
解答:

根据平方根定义, (a1)2=a1.\sqrt{(a - 1)^2} = |a - 1|.

因为 a<0a < 0 所以 a1<0a - 1 < 0 从而 a1=1a|a - 1| = 1 - a

原式化为 又因为 a<0a < 0 所以 2a3<02a - 3 < 0 因此 2a3=32a|2a - 3| = 3 - 2aa2(1a)=2a3. |a - 2 - (1 - a)| = |2a - 3|.

所以正确答案是 A

By the definition of square root, we get that (a1)2=a1.\sqrt{(a - 1)^2} = |a - 1|.

Since a<0,a < 0, we get that a1<0,a - 1 < 0, which means that a1=1a.|a - 1| = 1 - a.

The whole expression therefore simplifies to a2(1a)=2a3. |a - 2 - (1 - a)| = |2a - 3|. Since a<0,a < 0, we know that 2a3<0.2a - 3 < 0. This means that 2a3=32a.|2a - 3| = 3 - 2a.

Thus, A is the correct answer.

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